The 1,3-dimethyl unit is found in many natural products, including siphonarienal,[1 ] ionomycin,[2 ] scyphostatin,[3 ] and borrelidin (Figure [1 ]),[4 ] and the stereoselective synthesis of chiral 1,3-dimethyl units is considered an
important synthetic topic.[5 ] There are many methods available for the diastereo- and enantioselective synthesis
of anti - and syn -1,3-dimethyl units. The iterative Michael reaction of methyl groups under reagent
control is a widely employed method,[6 ] and iterative allylic substitution and alkylation of chiral enolates is also used.[7 ] Negishi’s Zr-catalyzed carboalumination (ZACA) reaction is a powerful method for
the preparation of 1,3-dimethyl units,[8 ] and Aggarwal recently reported an assembly-line synthesis that proceeds through
iterative homologation of boronic esters with chiral lithiated benzoate esters and
chloromethyllithium.[9 ] Some of the methods use asymmetric catalytic reactions.[6 ]
[8 ] In spite of these elegant methods, a procedure which is suitable for the large-scale
preparation of 1,3-dimethyl units is needed.
Figure 1 Natural products with a 1,3-dimethyl unit
We have already reported the asymmetric Michael reaction of an α,β-unsaturated aldehyde
with nitromethane catalyzed by a diphenylprolinol silyl ether[10 ] as an effective organocatalyst (Scheme [1 ]).[11 ] The sequential use of this Michael reaction would afford either the syn - or anti -1,3-dimethyl unit stereoselectively (Scheme [2 ]). The Michael reaction of nitromethane and crotonaldehyde catalyzed by (S )-diphenylprolinol silyl ether (S )-1a ,[12 ] followed by acetalization would provide 2 . A second Michael reaction of the generated nitroalkane 2 and crotonaldehyde, catalyzed by either (S )- or (R )-diphenylprolinol silyl ether, would then afford the desired anti - or syn -1,3-dimethyl unit, respectively. The realization of this scenario is described herein.
Scheme 1 An asymmetric Michael reaction catalyzed by a diphenylprolinol silyl ether
Scheme 2 The idea for the synthesis of anti - and syn -dimethyl units
The first Michael reaction of crotonaldehyde and nitromethane was carried out using
5 mol% of (S )-diphenylprolinol diphenylmethylsilyl ether (S )-1a
[12 ] as the catalyst in MeOH in the presence of 10 equivalents of H2 O to afford the Michael product, which was treated with HC(OMe)3 and a catalytic amount of TsOH in the same vessel to provide nitroacetal 2 in 94% yield and 90% ee (Scheme [3 ]). This reaction required four days to reach completion when THF was employed as
the solvent, as described previously,[13 ] but was complete within two days in MeOH and proceeded with excellent enantioselectivity.
Scheme 3 The initial Michael reaction of crotonaldehyde and nitromethane
The second Michael reaction of 2 and crotonaldehyde was then investigated using diphenylprolinol trimethylsilyl ether
(S )-1b as the catalyst (Table [1 ]). Alcohol 3 was obtained in 43% yield as a diastereomeric mixture after treatment of the Michael
product with NaBH4 (entry 1). To improve this yield, the reaction conditions were screened.
For the Michael reaction of a nitroalkane and an α,β-unsaturated aldehyde, we have
previously reported several reaction conditions. (1) For β-aryl α,β-unsaturated aldehydes,
the solvent was MeOH with an acid additive.[11a ] (2) For β-alkyl α,β-unsaturated aldehydes, the solvent was MeOH without an acid
additive.[11a ] (3) For β,β-disubstituted α,β-unsaturated aldehydes, neat conditions were employed
without an acid additive.[11b ] Other research groups have reported alternative reaction conditions: in the reaction
of a β-aryl α,β-unsaturated aldehyde, the Merck group reported the use of aqueous
THF in the presence of pivalic acid and B(OH)3 ,[14 ] whereas Wang and co-workers used EtOH with benzoic acid as an acid additive.[15 ]
When the reaction was conducted in MeOH with 10 equivalents of water, the product
was obtained in 43% yield after 7.5 hours (Table [1 ], entry 1); no reaction occurred without water (entry 2). Addition of an acid was
not effective in the present reaction (entry 3). The use of either THF or neat conditions
were also not suitable (entries 4–7). In these reactions, nitroalkane 2 was recovered in good yield,[16 ] while crotonaldehyde was consumed. One of the side products of crotonaldehyde was
found to be the self-aldol product, presumably formed via the dienamine intermediate
generated from crotonaldehyde and the catalyst. To suppress this side reaction, crotonaldehyde
was added slowly. However, the desired reaction did not occur because of a further
side reaction involving the formation of 1-methoxybut-2-en-1-ol, which would be generated
by the reaction of MeOH and crotonaldehyde (entry 8). To also suppress this side reaction,
slow addition of a solution of crotonaldehyde in THF was examined, which afforded
the desired product in 62% yield (entry 9).[17 ]
Table 1 The Effect of Solvent, Additive and Addition Time on the Asymmetric Michael Reaction
of Nitroalkane 2 and Crotonaldehydea
Entry
Solvent
H2 O (equiv)b
Time (h)
Yield (%)c
1
MeOH
10
7.5
43
2
MeOH
0
7.5
<5
3d
MeOH
10
2
<5
4
THF
10
28
<5
5
THF
0
28
<5
6
neat
10
28
<5
7
neat
0
28
<5
8e
MeOH
10
11
<5
9f
MeOH
10
11
62
a Unless noted otherwise, the reaction was performed by employing 2 (0.6 mmol), crotonaldehyde (1.2 mmol), and (S )-1b (0.12 mmol) in solvent (1.2 mL) with H2 O (6.0 mmol) (or without H2 O) at room temperature for the indicated time.
b Amount of water.
c Yield of purified product.
d Benzoic acid (20 mol%) was added.
e A MeOH solution of crotonaldehyde was added over 10 h.
f A THF solution of crotonaldehyde was added over 10 h.
The product, which contains three chiral centers, was obtained as a mixture of several
diastereomers. Denitration was then investigated. Alcohol 3 was converted into its benzoyl ester 4 . After optimization of the denitration conditions, it was found that the reaction
of 4 with n -Bu3 SnH proceeded at 150 °C to afford alcohol 5 in 68% yield with 2.2:1 diastereoselectivity (Scheme [4a ]).[18 ]
[19 ] To increase the diastereoselectivity, we further optimized the second Michael reaction
using an organocatalyst with a different silyl substituent. An improved result was
obtained when diphenylmethylsilyl ether (S )-1a
[12 ] was employed instead of trimethylsilyl ether (S )-1b to provide, after denitration, the product 6 with 3.7:1 diastereoselectivity (Scheme [4b ]). As we found that protection of the hydroxy moiety was not necessary during our
investigation of the denitration, we converted 3 into alcohol 6 according to the method shown in Scheme [4b ]. Although the diastereoselectivity was moderate, excellent enantioselectivity was
obtained (97% ee ). It is noteworthy that the enantioselectivity increased from 90% to 97% (vide infra ).
Scheme 4 (a) Denitration of alcohol 3 . (b) Optimized conditions for the second Michael reaction and subsequent denitration
Next, the generality of the asymmetric double Michael reaction was investigated (Table
[2 ]). Although the anti -1,3-dimethyl substituent was obtained with moderate diastereoselectivity, excellent
enantioselectivity was generated (entry 1). Both the 1,3-syn -dimethyl isomer and the 1,3-syn -methyl ethyl isomer were obtained with excellent diastereoselectivities and enantioselectivities
(entries 2 and 3). In the second Michael reaction, cinnamaldehyde was also a suitable
Michael acceptor, affording the syn - and anti -isomers with excellent stereoselectivity (entries 4 and 5). 3-Aryl-substituted propenals
could also be successfully employed. Notably, both an electron-deficient aryl, such
as that with a p -trifluoromethylphenyl substituent, and an electron-rich aryl, such as that with a
p -methoxyphenyl substituent, were suitable substrates (entries 6 and 7). Table [2 ] indicates that the diastereoselectivities are moderate to good and that they depend
on the substituents. However, the enantioselectivities of the final products are found
to be excellent (>95% ee) for both 1,3-anti - and 1,3-syn -isomers. It should be noted that the enantioselectivity increased in all the cases,
although that of the first Michael product 2 was 90%.
Table 2 The Two-Pot Synthesis of 1,3-Disubstituted Alkanolsa
Entry
Product
Cat.
Michael reaction yield (%)b
drc
Denitration yield (%)b
anti /syn
d
ee
d
1
S
60
nd
49
3.7:1
97
2
R
63
nd
51
1:10
98
3e
R
60
nd
44
1:>20
97
4
S
80
63:28:7:2
54
13:1
98
5
R
78
59:30:6:5
48
1:15
96
6
S
91
53:42:5:0
62
>20:1
>99
7
S
80
62:26:9:3
65
5.9:1
99
a First step (Michael reaction): Unless noted otherwise, the reactions were performed
by employing 2 (0.6 mmol), α,β-unsaturated aldehyde (1.2 mmol), (S )-1a or (R )-1a (0.12 mmol), and H2 O (6.0 mmol) in MeOH (1.2 mL) at room temperature via slow addition of the aldehyde
over 20 h and further stirring of the reaction mixture for 1 h. Second step (denitration
reaction): Unless noted otherwise, the reactions were performed by employing the Michael
adduct (0.4 mmol), n -Bu3 SnH (2.0 mmol), AIBN (0.32 mmol), and 1,3,5-trimethoxybenzene (14.0 mmol) at 250 °C
for 5 min.
b Yield of purified product.
c dr = diastereomer ratio in the Michael reaction determined by 1 H NMR spectroscopy; nd = not determined.
d Diastereomer ratio and enantiomeric excess were determined by HPLC analysis on a
chiral column.
e Slow addition over 40 h during the Michael reaction.
The double Michael product could also be transformed into the 1,3-disubstituted-2-oxo
derivative through a Nef reaction.[20 ] When anti -7 and syn -7 were treated with NaOMe and dimethyldioxirane (DMDO),[20a ] 1,3-anti - and 1,3-syn -dimethylketones (anti -8 and syn -8 ), respectively, were obtained in good yields, albeit with a slight decrease of the
diastereoselectivity and enantioselectivity (Scheme [5 ]).
Scheme 5 Transformation of Michael products 7 into 1,3-disubstituted-2-oxo derivatives syn -8 and anti -8
Although the enantiomeric excess of the first Michael product was 90%, the double
Michael product was formed with an excellent enantioselectivity that was much higher
than that of the first Michael reaction. The origin of this enhanced enantioselectivity
can be explained as follows (Scheme [6 ]). In the first Michael reaction, 2 and ent -2 were generated in a 95:5 ratio, in which 2 was formed predominantly rather than ent -2 . When 2 reacted with crotonaldehyde catalyzed by (S )-1a , in which the (R )-isomer of the newly generated methyl group would be predominantly generated,[11 ] anti -3 was formed predominantly, while the generation of (S )-isomers such as syn -3 and anti -ent -3 would be minor. As ent -2 is generated in a small amount in the first reaction and the generation of anti -ent -3 is also a minor reaction path in the second Michael reaction, the amount of anti -ent -3 would be very little. If the stereoselectivity of the newly generated stereocenter
in the second Michael reaction is 95:5, the ratio of anti -3 and anti -ent -3 would be 90.25:0.25. Thus, the ee in the final product 3 is much higher than that of the first Michael product 2 .
The present method was applied to the asymmetric synthesis of the side chain of pneumocandin
B0 (9 ) (Figure [2 ]).[21 ] Pneumocandin B0 was isolated from the fermentation broth of the fungus Glarea lozoyensis by Merck & Co. Its fungal-specific mode of action is inhibition of the biosynthesis
of β-(1,3)-d -glucan, which is an essential cell wall component of many pathogenic fungi. The stereoselective
synthesis of the (10R ,12S )-dimethylmyristoyl side chain 10 of this compound through the use of Enders’ RAMP method and diastereoselective alkylation
of the chiral enolate has previously been reported.[21c ]
Scheme 6 The reason for the higher ee of the second Michael product
Figure 2 The structure of pneumocandin B0 (9 ) and its side chain 10
Our synthesis of the side chain 10 started with the Michael reaction of nitromethane and crotonaldehyde catalyzed by
diphenylprolinol silyl ether (S )-1a . Subsequent acetalization provided 2 in 94% yield with 90% ee . The second Michael reaction with crotonaldehyde proceeded in the presence of (R )-1a , followed by treatment with NaBH4 to afford alcohol syn -3 in 63% yield. The enantioselectivity of syn -3 is 98%, which was determined after denitration (see Table [2 ], entry 2). Alcohol syn -3 was converted into haloalkane 11 in 69% yield by reaction with Ph3 P and I2 .[22 ] Dehalogenation and denitration occurred in the same pot[23 ] by treatment with n -Bu3 SnH and AIBN at 150 °C[18 ] to afford acetal 12 in 73% yield. Treatment of acetal 12 with aqueous HCl gave aldehyde 13 , which was used in the next step without purification. The Julia–Kocienski reaction
with 14 proceeded smoothly to afford (E )-alkene 15 in 56% yield over two steps.[24 ] Hydrogenation followed by hydrolysis using aqueous NaOH afforded the side chain
of pneumocandin B0 10 in 72% yield over two steps (Scheme [7 ]). The physical properties of synthetic 10 were identical in all respects to the reported data.[21d ]
Scheme 7 Synthesis of the side chain of pneumocandin B0
In conclusion, we have developed an efficient method for the synthesis of chiral 1,3-dimethyl
units through a double Michael reaction of an aldehyde and nitroalkane catalyzed by
a diphenylprolinol silyl ether. There are several noteworthy features of this reaction.
Either 1,3-syn - or 1,3-anti -dimethyl units can be selectively synthesized depending on the appropriate choice
of enantiomer of the diphenylprolinol silyl ether catalyst. The excellent optical
purity of the double Michael product was much higher than that of the first Michael
reaction because of the ‘meso -trick’. In addition to the 1,3-dimethyl unit, both 1,3-methyl alkyl and 1,3-methyl
aryl units can be prepared. Finally, the side chain of pneumocandin B0 was enantioselectively synthesized by using the present method as a key step.
Scheme 8
